On DevOps and Snowflakes

One can hardly swing a proverbial cat in IT these days without hearing people talking about DevOps.  DevOps is the hot new topic in the industry picking up from where the talk of cloud left off and to hear people talk about it one might believe that traditional systems administration is already dead and buried.

First we must talk about what we mean by DevOps.  This can be confusing because, like cloud, an older term is often being stolen to mean something different or, at best, related to something that already existed.  Traditional DevOps was the merging of developer and operational roles.  In the 1960s through the 1990s, this was the standard way of running systems.  In this world the people who wrote the software were generally the same ones who deployed and maintained it.  Hence the merging of “developer” and “operations”, operations being a semi-standard term for the role of system administrator.  These roles were not commonly separated until the rise of the “IT Department” in the 1990s and the 2000s.  Since then, the return to the merging of the two roles has started to rise in popularity again primarily because of the way that the two can operate together with great value in many modern, hosted, web application situations.

Where DevOps is often talked about today is not as a strict merging of the developers and the operations staff but as a modification to the operations staff with a much higher focus on coding not the application itself but in defining application infrastructures as code as a natural extension of cloud architectures.  This can be rather confusing at first.  What is important to note is that traditional DevOps is not what is commonly occurring today but a new “fake” DevOps where developers remain developers and operations remains operations but operations has evolved into a new “code heavy” role that continues to focus on managing servers running code provided by the developers.

What is significant today is that the role of the system administrator has begun to diverge into two related, but significantly different roles, one of which is improperly called DevOps by most of the industry today (most of the industry being too young to remember when DevOps was the norm, not the exception and certainly not something new and novel.)  I refer to these two aspects of the system administrator role here as the DevOps and the Snowflake approaches.

I use the term Snowflake to refer to traditional architectures for systems because each individual server can be seen as a “unique Snowflake.”  They are all different, at least insofar as they are not somehow managed in such a way as to keep them identical.  This doesn’t mean that they have to be all unique, just that they retain the potential to be.  In traditional environments a system administrator will log into each server individually to work on them.  Some amount of scripting is common to ease administration tasks but at its core the role involves a lot of time working on individual systems.

Easing administration of Snowflake architectures often involved attempts to minimize differences between systems in reasonable ways.  This generally starts with things like choosing a single standard operating system and version (Windows 2012 R2 or Red Hat Enterprise Linux 7) rather than allowing every server installation to be a different OS or version.  This standardization may seem basic but many shops lack this standardization even today.

A next step is commonly creating a standard deployment methodology or a gold master image that is used for making all systems so that the base operating system and all base packages, often including system customization, monitoring packages, security packages, authentication configuration and similar modifications are standard and deployed uniformly.  This provides a common starting point for all systems to minimize divergence.  But technically they only ensure a standard starting point and over time divergence in configuration must be anticipated.

Beyond these steps, Snowflake environments typically use custom, bespoke administration scripts or management tools to maintain some standardization between systems over time.  The more commonalities that exist between systems the easier they are to maintain and troubleshoot and the less knowledge is needed by the administration staff.  More standardization means fewer surprises, fewer unknowns and much better testing capabilities.

In a single system administrator environment with good practices and tooling, Snowflake environments can take on a high degree of standardization.  But in environments with many system administrators, especially those supported around the clock from many regions, and with a large number of systems, standardization, even with very diligent practices, can become very difficult.  And that is even before we tackle the obvious issues surrounding the fact that different packages and possibly package versions are needed on systems that perform different roles.

The DevOps approach grows organically out of the cloud architecture model.  Cloud architecture is designed around automatically created and automatically destroyed, broadly identical systems (at least in groups) that are controlled through a programmatic interface or API.  This model lends itself, quite obviously, to being controlled centrally through a management system rather than through the manual efforts of a system administrator.  Manual administration is effectively impossible and completely impractical under this model.  Individual systems are not unique like in the Snowflake model and any divergence will create serious issues.

The idea that has emerged from the cloud architecture world is one that systems architecture should be defined centrally “in code” rather than on the servers themselves.  This sounds confusing at first but makes a lot of sense when we look at it more deeply.  In order to support this model a new type of systems management tool that has yet to take on a really standard name but is often called a systems automation tool, DevOps framework, IT automation tool or simply “infrastructure as code” tool has begun to emerge.  Common toolsets in this realm include Puppet, Chef, CFEngine and SaltStack.

The idea behind these automation toolsets is that a central service is used to manage and control all systems.  This central authority manages individual servers by way of code-based descriptions of how the system should look and behave.  In the Chef world, these are called “recipes” to be cute but the analogy works well.  Each system’s code might include information such as a list of which packages and package versions should be installed, what system configurations should be modified and files to be copied to the box.  In many cases decisions about these deployments or modifications are handled through potentially complex logic and hence the need for actual code rather than something more simplistic such as markup or templates.  Systems are then grouped by role and managed as groups.  The “web server” role might tell a set of systems to install Apache and PHP and configure memory to swap very little.  The “SQL Server” role might install MS SQL Server and special backup tools only used for that application and configure memory to be tuned as desired for a pool of SQL Server machines.  These are just examples.  Typically an organization would have a great many roles, some may be generic such as “web server” and others much more specific to support very specific applications.  Roles can generally be layered, so a system might be both a “web server” and a “java server” getting the combined needs of both met.

These standard definitions mean that systems, once designated as belonging to one role or another, can “build themselves” automatically.  A new system might be created by an administrator requesting a system or a capacity monitoring system might decide that additional capacity is needed for a role and spawn new server instances automatically without any human intervention whatsoever.  At the time that the system is requested, by a human or automatically, the role is designated and the system will, by way of the automation framework, transform itself into a fully configured and up to date “node.”  No human system administration intervention required.  The process is fast, simple and, most importantly, completely repeatable.

Defining systems in code has some non-obvious consequences.  One is that backups of complete systems are no longer needed.  Why backup a system that you can recreate, with minimum effort, almost instantly?  Local data from database systems would need to be backed up but only the database data, not the entire system.  This can greatly reduce strain on backup infrastructures and make restore processes faster and more reliable.

The amount of documentation needed for systems already defined in code is very minimal.  In Snowflake environments the system administrator needs to maintain documentation specific to every host and maintain that documentation manually. This is very time consuming and error prone.   Systems defined by way of central code need little to no documentation and the documentation can be handled at a group level, not the individual node level.

Testing systems that are defined in code is easy to do as well.  You can create a system via code, test it and know that when you move that definition into production that the production system will be created repeatably exactly as it was created in testing.  In Snowflake environments it is very common to have testing practices that attempt to do this but do so through manual efforts and are prone to being sloppy and not exactly repeatable and very often politics will dictate that it is faster to mimic repeatability than to actually strive for it.  Code defined systems bypass these problems making testing far more valuable.

Outside of needing to define a number of nodes to exist within each role, the system can reprovision an entire architecture, from scratch, automatically.  Rebuilding after a disaster or bringing up a secondary site can be very quickly and easily done.  Also moving between locally hosted systems and remotely hosted systems including those from companies like Amazon, Microsoft, IBM, Rackspace and others is extremely easy.

Of course, in the DevOps world there is a great value to using cloud architectures to enable the most extreme level of automation but using cloud architectures is unnecessary to leverage these types of tools.  And, of course, having a code defined architecture could be used partially while manual administration could be implemented too for a hybrid approach but this is rarely recommended on individual systems.  It is generally far better to have two environments, one that is managed as Snowflakes and one that is managed as DevOps when the two approaches are mandated.  This makes  a far better hybridization.  I have seen this work extremely well in an enterprise environment with more scores of thousands of “Snowflake” servers each very unique but with a dedicated environment of ten thousands nodes that was managed in a DevOps manner because all of the nodes were to be identical and interchangeable using one of two possible configurations.  Hybridization was very effective.

The DevOps approach, however, comes with major caveats as well.  The skill sets necessary to manage a system in this way are far greater than those needed for traditional systems administration as, at a minimum, all traditional systems administration knowledge is still needed plus solid programming knowledge typically of modern languages like Python and Ruby and knowledge of the specific frameworks in question as well.  This extended knowledge base requirement means that DevOps practitioners are not only rare but expensive too.  It also means that university education, already far short of preparing either systems administrators or developers for the professional world are now farther still from preparing graduates to work under a DevOps model.

System administrators working in each of these two camps have a tendency to see all systems as needing to fit into their own mold. New DevOps practitioners often believe that Snowflake systems are legacy and need to be updated.  Snowflake (traditional) admins tend to see the “infrastructure as code” movement as silly, filled with unnecessary overhead, overly complicated and very niche.

The reality is that both approaches have a tremendous amount of merit and both are going to remain extremely viable.  Both make sense for very different workloads and large organizations, I suspect, will commonly see both in place via some form of hybridization.  In the SMB market where there are typically only a tiny number of servers, no scaling leverage to justify cloud architectures and a high disparity between systems, I suspect that DevOps will remain almost indefinitely outside of the norm as the overhead and additional skills necessary to make it function are impractical or even impossible to acquire.  Larger organizations have to look at their workloads.  Many traditional workloads and much of traditional software is not well suited to the DevOps approach, especially cloud automation, and will either require hybridization or an impractically high level of coding on a per system basis making the DevOps model impossible to justify.  But workloads built on web architectures or that can scale horizontally extremely well will benefit heavily from the DevOps model at scale.  This could apply to large enterprise companies or smaller companies likely producing hosted applications for external consumption.

This difference in approach means that, in the United States for example, most of the US is comprised of companies that will remain focused on the Snowflake management model while some east coast companies could evaluate the DevOps model effectively and begin to move in that direction.  But on the west coast where more modern architectures and a much larger focus on hosted applications and applications for external consumption are the driving economic factors, DevOps is already moving from newcomer to mature, established normalcy.  DevOps and Snowflake approaches will likely remain heavily segregated by regions in this way just as IT, in general, sees different skill sets migrate to different regions.  It would not be surprising to see DevOps begin to take hold in markets such as Austin where traditional IT has performed rather poorly.

Neither approach is better or worse, they are two different approaches servicing two very different ways of provisioning systems and two different fundamental needs of those systems.  With the rise of cloud architectures and the DevOps model, however, it is critically important that existing system administrators understand what the DevOps model means and when it applies so that they can correctly evaluate their own workloads and unique needs.  A large portion of the traditional Snowflake system administration world will be migrating, over time, to the DevOps model.  We are very far from reaching a steady state in the industry as to the balance of these two models.

Originally published on the StorageCraft Blog.

Practical RAID Performance

Choosing a RAID level is an exercise in balancing many factors including cost, reliability, capacity and, of course, performance.  RAID performance can be difficult to understand especially as different RAID levels use different techniques and behave rather differently from each other in some cases.  In this article I want to explore the common RAID levels of RAID 0, 5, 6 and 10 to see how performance differs between them.

For the purposes of this article, RAID 1 will be assumed to be a subset of RAID 10.   This is often a handy way to think of RAID 1 – as simply being a RAID 10 array with only a single mirrored pair member.  As RAID 1 is truly a single pair RAID 10 and behaves as such this works wonderfully for making RAID performance easy to understand as it simply maps into the RAID 10 performance curve.

There are two types of performance to look at with all storage: reading and writing.  In terms of RAID reading is extremely easy and writing is rather complex.  Read performance is effectively stable across all RAID types.  Writing, however, is not.

To make discussing performance easier we need to define a few terms as we will be working with some equations. In our discussions we will use N to represent the total number of drives, often referred to as spindles, in our array and we will use X to refer to the performance of each drive individually.  This allows us to talk in terms of relative performance as a factor of the drive performance allowing us to abstract away the RAID array and not have to think in terms of raw IOPS.  This is important as IOPS are often very hard to define but we can compare performance in a meaningful way by speaking to it in relationship to the individual drives within the array.

It is also important to remember that we are only talking about the performance of the RAID array itself, not an entire storage subsystem.  Artifacts such as memory caches and solid state caches will do amazing things to alter the overall performance of a storage subsystem, but do not fundamentally change the performance of the RAID array itself under the hood.  There is no simple formula for determining how different cache options will impact the overall performance but suffice it to say that it can be very dramatic but this depends heavily not only on the cache choices themselves but also heavily upon workload. Even the biggest, fastest, most robust cache options cannot change the long term, sustained performance of an array.

RAID is complex and many factors influence the final performance.  One is the implementation of the RAID system itself.  A poor implementation might cause latency or may fail to take advantage of the available spindles (such as having a RAID 1 array read only from a single disk instead of from both simultaneously!)  There is no easy way to account for deficiencies in specific RAID implementations so we must assume that all are working to the limits of the specification as, indeed, any enterprise RAID system will do. It is primarily hobby and consumer RAID systems that fail to do this.

Some types of RAID also have dramatic amounts of computational overhead associated with them while others do not.  Primarily parity RAID levels require heavy processing in order to handle write operations with different levels having different amounts of computation necessary for each operation.  This introduces latency, but does not curtail throughput.  This latency will vary, however, based on the implementation of the RAID level as well as on the processing capability of the system in question.  Hardware RAID will use something like a general purpose CPU (often a Power or ARM RISC processor) or a custom ASIC to handle this while software RAID hands this off to the server’s own CPU.  Often the server CPU is actually faster here but consumes system resources.  ASICs can be very fast but are expensive to produce.  This latency impacts storage performance but is very difficult to predict and can vary from nominal to dramatic.  So I will mention the relative latency impact with each RAID level but will not attempt to measure it.  In most RAID performance calculations, this latency is ignored but it is important to understand that it is present and could, depending on the configuration of the array, have a noticeable impact on a workload.

There is, it should be mentioned, a tiny performance impact to read operations due to efficiencies in the layout of data on the disk itself.  Parity RAID requires there to be data on the disks that is useless during a healthy read operation but cannot be used to speed it up.  The actually results in it being slightly slower.  But this impact is ridiculously small and is normally not measured and so can be ignored.

Factors such as stripe size also impact performance, of course, but as that is configurable and not an intrinsic artifact in any RAID level I will ignore it here.  It is not a factor when choosing a RAID level itself but only in configuring one once chosen.

The final factor that I want to mention is the read to write ratio of storage operations.  Some RAID arrays will be used almost purely for read operations, some almost solely for write operations but most use a blend of the two, likely something like eighty percent read and twenty percent write.  This ratio is very important in understanding the performance that you will get from your specific RAID array and understanding how each RAID level will impact you.  I refer to this as the read/write blend.

We measure storage performance primarily in IOPS.  IOPS stands for Input/Output Operations Per Second (yes, I know that the letters don’t line up well, it is what it is.)  I further use the terms RIOPS for Read IOPS, WIOPS for Write IOPS and BIOPS for Blended IOPS which would come with a ration 80/20 or whatever.  Many people talk about storage performance with a single IOPS number.  When this is done they normally mean Blended IOPS at 50/50.  However, rarely does any workload run at 50/50 so that number can be extremely misleading.  Two numbers, RIOPS and WIOPS is what is needed to understand performance and these two together can be used to find any IOPS Blend that is needed.   For example, a 50/50 blend is as simple as (RIOPS * .5) + (WIOPS * .5).  The more common 80/20 blend would be (RIOPS * .8) + (WIOPS * .2).

Now that we have established some criteria and background understanding we will delve into our RAID levels themselves and see how performance varies across them.

For all RAID levels, the Read IOPS number is calculated using NX.  This does not address the nominal overhead numbers that I mention above, of course.  This is a “best case” number but the real world number is so close that it is very practical to simply use this formula.  Since take the number of spindles (N) and multiple by the IOPS performance of an individual drive (X).  Keep in mind that drives often have different read and write performance so be sure to use the drives Read IOPS rating or tested speed for the Read IOPS calculation and the Write IOPS rate or tested speed for the Write IOPS calculation.

RAID 0

RAID 0 is the easiest RAID level to understand because there is effectively no overhead to worry about, no resources consumed to power it and both read and write get the full benefit of every spindle, all of the time.  So for RAID 0 our formula for write performance is very simple: NX.  RAID 0 is always the most performant RAID level.

An example would be an eight spindle RAID 0 array.  If an individual drive in the array delivers 125 IOPS then our calculation would be from N = 8 and X = 125 so 8 * 125 yielding 1,000 IOPS.  Since both read and write IOPS are the same here, it is extremely simple as we get 1K RIOPS, 1K WIOPS and 1K with any blending thereof.  Very simple.  If we didn’t know the absolute IOPS of an individual spindle we could refer to an eight spindle RAID 0 as delivering 8X Blended IOPS.

RAID 10

RAID 10 has the second simplest RAID level to calculate.  Because RAID 10 is a RAID 0 stripe of mirror sets, we have no overhead to worry about from the stripe but each mirror has to write the same data twice in order to create the mirroring.  This cuts our write performance in half compared to a RAID 0 array of the same number of drives.  Giving us a write performance formula of simply: NX/2  or .5NX.

It should be noted that at the same capacity, rather than the same number of spindles, RAID 10 has the same write performance as RAID 0 but double the read performance – simply because it requires twice as many spindles to match the same capacity.

So an eight spindle RAID 10 array would be N = 8 and X = 125 and our resulting calculation comes out to be (8 * 125)/2 which is 500 WIOPS or 4X WIOPS.  A 50/50 blend would result in 750 Blended IOPS (1,000 Read IOPS and 500 Write IOPS.)

This formula applies to RAID 1, RAID 10, RAID 100 and RAID 01 equally.

Uncommon options such as triple mirroring in RAID 10 would alter this write penalty.  RAID 10 with triple mirroring would be NX/3, for example.

RAID 5

While RAID 5 is deprecated and should never be used in new arrays I include it here because it is a well known and commonly used RAID level and its performance needs to be understood.  RAID 5 is the most basic of the modern parity RAID levels.  RAID 2, 3 & 4 are no longer found in production systems and so we will not look into their performance here.  RAID 5, while not recommended for use today, is the foundation of other modern parity RAID levels so is important to understand.

Parity RAID adds a somewhat complicated need to verify and re-write parity with every write that goes to disk.  This means that a RAID 5 array will have to read the data, read the parity, write the data and finally write the parity.  Four operations for each effective one.  This gives us a write penalty on RAID 5 of four.  So the formula for RAID 5 write performance is NX/4.

So following the eight spindle example where the write IOPS of an individual spindle is 125 we would get the following calculation: (8 * 125)/4 or 2X Write IOPS which comes to 250 WIOPS.  In a 50/50 blend this would result in 625 Blended IOPS.

RAID 6

RAID 6, after RAID 10, is probably the most common and useful RAID level in use today.  RAID 6, however, is based off of RAID 5 and has another level of parity.  This makes it dramatically safer than RAID 5, which is very important, but also imposes a dramatic write penalty as each write operation requires the disks to read the data, read the first parity, read the second parity, write the data, write the first parity and then finally write the second parity.  This comes out to be a six times write penalty, which is pretty dramatic.  So our formula is NX/6.

Continuing our example we get (8 * 125)/6 which comes out to ~167 Write IOPS or 1.33X.  In our 50/50 blend example this is a performance of  583.5 Blended IOPS.  As you can see, parity writes cause a very rapid decrease in write performance and a noticeable drop in blended performance.

RAID 7 (aka RAID 5.3 or RAID 7.3)

RAID 7 is a somewhat non-standard RAID level with triple parity based off of the existing single parity of RAID 5 and the existing double parity of RAID 6.  The only current implementation of RAID 7 is ZFS’ RAIDZ3.  Because RAID 7 contains all of the overhead of both RAID 5 and RAID 6 plus the additional overhead of the third parity component we have a write penalty of a staggering eight times.  So our formula for finding RAID 7 write performance is NX/8.

In our example this would mean that (8 * 125)/8 would come out to 125 Write IOPS or 1X.  So with eight drives in our array we would get only the write performance of a single, stand alone drive.  That is significant overhead.  Our blended 50/50 IOPS would come out to only 562.5.

Complex RAID

Complex RAID levels or Nested RAID levels such as RAID 50, 60, 61, 16, etc. can be found using the information above and breaking the RAID down into its components and applying each using the formulæ provided above.  There is no simple formula for these levels because they have varying configurations.  It is necessary to break them down into their components and apply the formulæ multiple times.

RAID 60 with twelve drives, two sets of six drives, where each drive is 150 IOPS would be done with two RAID 6s.  It would be the NX of RAID 0 where N is two (for two RAID 6 arrays) and the X is the resultant performance of each RAID 6.   Each RAID 6 set would be (6 * 150)/6.  So the full array would be 2((6 * 150)/6).  Which results in 300 Write IOPS.

The same example as above but configured as RAID 61, a mirrored pair of RAID 6 arrays, would be the same performance per RAID 6 array, but applied to the RAID 1 formula which is NX/2 (where X is the resultant performance of the each RAID array.)  So the final formula would be 2((6 * 150)/6)/2 coming to 150 Write IOPS from twelve drives.

Performance as a Factor of Capacity

When we are producing RAID performance formulæ we think of these in terms of the number of spindles which is incredibly sensible.  This is very useful in determining the performance of a proposed array or even an existing one where measurement is not possible and allows us to compare the relative performance between different proposed options.  It is in these terms that we universally think of RAID performance.

This is not always a good approach, however, because typically we look at RAID as a factor of capacity rather than of performance or spindle count.  It would be very rare, but certainly possible, that someone would consider an eight drive RAID 6 array versus an eight drive RAID 10 array.  Once in a while this will occur due to a chassis limitation or some other, similar reason.  But typically RAID arrays are viewed from the standpoint of total array capacity (e.g. usable capacity) rather than spindle count, performance or any other factor.  It is odd, therefore, that we should then switch to viewing RAID performance as a function of spindle count.

If we change our viewpoint and pivot upon capacity as the common factor, while still assuming that individual drive capacity and performance (X) remains constant between comparators then we arrive at a completely different landscape of performance.  In doing this we see, for example, that RAID 0 is no longer the most performant RAID level and that read performance varies dramatically instead of being a constant.

Capacity is a fickle thing but we can distill it out to the number of spindles necessary to reach desired capacity.  This makes this discussion far easier.  So our first step is to determine our spindle count needed for raw capacity.  If we need a capacity of 10TB and are using 1TB drives, we would need ten spindles, for example.  Or if we need 3.2TB and are using 600GB drives we would need six spindles.  We will, different than before, refer to our spindle count as R.  As before, performance of the individual drive is represented as X.  (R is used here to denote that this is the Raw Capacity Count, rather that the total Number of spindles.)

RAID 0 remains simple, performance is still RX as there are no additional drives.  Both read and write IOPS are simply NX.

RAID 10 has RX Write IOPS but 2RX Read IOPS.  This is dramatic.  Suddenly when viewing performance as a factor of stable capacity we find that RAID 10 has double read performance over RAID 0!

RAID 5 gets slightly trickier.  Write IOPS would be expressed as ((R + 1) * X)/4.  The Read IOPS are expressed as ((R +1) * X).

RAID 6, as we expect, follows the pattern that RAID 5 projects.  Write IOPS for RAID 6 are ((R + 2) * X)/6.  And the Read IOPS are expressed as ((R + 2) * X).

RAID 7 falls right in line.  RAID 7 Write IOPS would be ((R + 3) * X)/8.  And the Read IOPS are ((R + 3) * X).

This vantage point changes the way that we think about performance and, when looking purely at read performance, RAID 0 becomes the slowest RAID level rather than the fastest and RAID 10 becomes the fastest for both read and write no matter what the values are for R and X!

If we take a real world example of 10 2TB drives to achieve 20TB of usable capacity with each drive having 100 IOPS of performance and assume a 50/50 blend, the resultant IOPS would be:  RAID 0 with 1,000 Blended IOPS, RAID 10 with 1,500 Blended IOPS (2,000 RIOPS / 1,000 WIOPS), RAID 5 with 687.5 Blended IOPS (1,100 RIOPS / 275 WIOPS), RAID 6 with 700 Blended IOPS (1,200 RIOPS / 200 WIOPS) and finally RAID 7 with 731.25 Blended IOPS (1,300 RIOPS / 162.5 WIOPS.)  RAID 10 is a dramatic winner here.

Latency and System Impact with Software RAID

As I have stated earlier, RAID 0 and RAID 10 have, effectively, no system overhead to consider.  The mirroring operation requires essentially no computational effort and is, for all intents and purposes, immeasurably small.  Parity RAID does have computational overhead and this results in latency at the storage layer and system resources being consumed.  Of course, if we are using hardware RAID those resources are dedicated to the RAID array and have no function but to be consumed in this role.  If we are using software RAID, however, these are general purpose system resources (primarily CPU) that are consumed for the purposes of the RAID array processing.

The impact to even a very small system with a large amount of RAID is still very small but it can be measured and should be considered, if only lightly.  Latency and system impact are directly related to one another.

There is no simple way to state latency and system impact for different RAID levels except in this way: RAID 0 and RAID 10 have effectively no latency or impact, RAID 5 has some latency and impact, RAID 6 has roughly twice as much computational latency and impact as RAID 5 and RAID 7 has roughly triple the computational latency and impact as RAID 5.

In many cases this latency and system impact will be so small that they cannot be measured with standard system tools and as modern processors become increasingly powerful the latency and system impact will continue to diminish.  Impact has been considered negligible for RAID 5 and RAID 6 systems on even low end, commodity hardware since approximately 2001.  But it is possible on heavily loaded systems with a large amount of parity RAID activity that there could be contention between the RAID subsystem and other processes requiring system resources.

Reference: The IT Hollow – Understanding the RAID Penalty

Article originally posted to the StorageCraft Blog – RAID Performance.